Solution 1 :
WITH t
AS (SELECT sal, ename, DENSE_RANK () OVER (ORDER BY sal DESC) AS rnk
FROM emp)
SELECT sal, ename
FROM t
WHERE rnk IN (2);
--WHERE Rnk IN (1,2,3);
OR
SELECT ename, sal, RANK
FROM (SELECT ename, sal, DENSE_RANK () OVER (ORDER BY sal DESC) RANK
FROM emp)
WHERE RANK = 2
Solution 2 :
SELECT MAX(SAL) FROM EMP WHERE SAL NOT IN (SELECT MAX(SAL) FROM EMP)
Solution 3 :
SELECT MAX (sal)
FROM emp
WHERE sal IN (SELECT sal FROM emp
MINUS
SELECT MAX (sal) FROM emp)